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Next we replace each of x1, x2,
and x3 by x in our two expressions for M.
This results in
Thus we see that
for
k = 0, 1, 2, 3 is the number of ways of choosing a subset of k
elements from a set S of 3 elements. Similarly, one can see that
the number of ways of choosing k elements from a set of n
elements is
For example, the set {1, 2, 3, 4, 5} with 5 elements has
subsets
having 3 elements. Since
it is not too difficult to write out all ten of these subsets as
If we drop the braces enclosing the elements of each subset, the resulting
sequence is said to be a combination of 3 things chosen from
the set {1, 2, 3, 4, 5}. Thus the ten combinations of 3 things chosen from
this set of 5 objects are
| 1, 2, 3; | 1, 2, 4; | 1, 2, 5; | 1, 3, 4; | 1, 3, 5; |
| 1, 4, 5; | 2, 3, 4; | 2, 3, 5; | 2, 4, 5; | 3, 4, 5. |
Note that changing the order in which the objects of a combination are
written does not change the combination. For example, 1, 2, 4 is the same
combination as 1, 4, 2.
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Tuesday, May 12, 1998